HomeMaths Problems (quite literally)
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Maths Problems (quite literally)
by Shemuel 2008-07-18, 17:12
Last edited by Shemuel on 2008-07-18, 17:13; edited 1 time in total
Shemuel- Captain
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Re: Maths Problems (quite literally)
by Shemuel 2008-07-18, 17:13
I've made it a link, and I'm putting it in general chat
Shemuel- Captain
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Re: Maths Problems (quite literally)
by Earthdeath 2008-07-18, 17:16
LOL.i have seen 2 of them before.
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Re: Maths Problems (quite literally)
by Darkjedi 2008-07-18, 17:43
The top stuff is all trig. I learned all that stuff last year. LOL!Shemuel wrote:Maths Problems (quite literally)
www.eglobe1.com/index.php/2006/07/18/funny-mathematics-answer/
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Re: Maths Problems (quite literally)
by Earthdeath 2008-07-18, 17:54
i found that stuff really boring.
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Re: Maths Problems (quite literally)
by Shemuel 2008-07-18, 17:56
How about this then:
Theorem : 3=4
Proof:
Suppose:
a + b = c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganising:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3
Theorem : All numbers are equal to zero.
Proof: Suppose that a=b. Then
a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
a = 0
Theorem : 3=4
Proof:
Suppose:
a + b = c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganising:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3
Theorem : All numbers are equal to zero.
Proof: Suppose that a=b. Then
a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
a = 0
Shemuel- Captain
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Re: Maths Problems (quite literally)
by raffitz 2008-07-18, 18:32
Heh.... Nice....
I had already seen the problems, as someone sent it to me via e-mail somewhen....
I had already seen the problems, as someone sent it to me via e-mail somewhen....
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Re: Maths Problems (quite literally)
by Earthdeath 2008-07-19, 16:31
i hope i never have to do those again.
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Re: Maths Problems (quite literally)
by Darkjedi 2008-07-20, 02:05
What do you expect from a former hacker?Shemuel wrote:Only last year?
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Re: Maths Problems (quite literally)
by Earthdeath 2008-07-20, 07:52
you could have hacked the answers from a computer.
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Re: Maths Problems (quite literally)
by Darkjedi 2008-07-21, 23:30
Well, that doesn't work when you're learning from a book. 
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